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Sut i ddod o hyd i safle'r rhif cyntaf / olaf mewn llinyn testun yn Excel?

Er enghraifft, mae gennych chi restr o linyn testun sy'n gymysgedd o lythrennau a rhifau. Os ydych chi am ddod o hyd i safle'r rhif cyntaf neu'r rhif olaf ym mhob llinyn, beth fyddech chi'n ei wneud? Mewn gwirionedd, bydd defnyddio fformiwla yn eich helpu i ddod o hyd i safle rhif cyntaf / olaf yn gyflym mewn llinyn testun penodol. Yn y tiwtorial hwn, byddwn yn dangos i chi fanylion delio â'r broblem hon.

Darganfyddwch safle'r rhif cyntaf yn y llinyn testun yn Excel
Darganfyddwch safle'r rhif olaf yn y llinyn testun yn Excel

Darganfyddwch safle'r rhif cyntaf yn y llinyn testun yn Excel

Fel y dangosir y screenshot isod, ar gyfer dod o hyd i safleoedd rhifau cyntaf yn y tannau testun, gwnewch fel a ganlyn.

1. Dewiswch y gell B2, copïwch a gludwch un o'r fformiwla isod i'r Bar Fformiwla:

1). Fformiwla 1: = MIN (CHWILIO ({0,1,2,3,4,5,6,7,8,9}, A2 & "0123456789"));

2). Fformiwla 2: =MATCH(TRUE,ABS(CODE(MID(A2,ROW($A$1:INDEX(A:A,LEN(A2))),1))-52.5)<5,0) + Ctrl + Symud + Rhowch;

3). Fformiwla 3: =MIN(IF(ISERROR(FIND({1;2;3;4;5;6;7;8;9;0},A2)),"",FIND({1;2;3;4;5;6;7;8;9;0},A2))).

2. Yna mae safle rhif cyntaf y llinyn cyntaf yn cael ei arddangos yn y gell B2. Nawr llusgwch y Llenwch Trin i lawr i gell B7 i lenwi'r ystod isod.

Yna rhestrir holl swyddi rhif cyntaf y tannau cyfan.

Darganfyddwch safle'r rhif olaf yn y llinyn testun yn Excel

Ar ôl dod o hyd i safle rhif cyntaf, rydyn ni nawr yn dechrau dod o hyd i safle'r rhif olaf mewn tannau.

Yn yr adran hon, mae dau fformiwla i chi.

Fformiwla 1: = MAX (OS (ISNUMBER (GWERTH (MID (A2, ROW (INDIRECT ("1:" & LEN (A2)), 1))), ROW (INDIRECT ("1:" & LEN (A2))) ) + Ctrl + Symud + Rhowch;

Fformiwla 2: =MAX(IFERROR(FIND({1,2,3,4,5,6,7,8,9,0},A2,ROW(INDIRECT("1:"&LEN(A2)))),0)) + Ctrl + Symud + Rhowch

1. Dewiswch gell B2, copïo a gludo un o'r fformwlâu uchod i'r Bar Fformiwla, yna pwyswch Ctrl + Shift + Rhowch allweddi ar yr un pryd. Yna gallwch weld yr arddangosfeydd canlyniad yn B2.

2. Dewiswch y B2, llusgwch y Llenwch Trin i lawr i gell B7 i lenwi'r amrediad yn awtomatig.

Yna fe gewch swyddi o holl rifau olaf y llinyn testun cyfan ar unwaith.

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Comments (15)
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Wolfgang
Wolfgang
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Ich habe gerade diese Lösung ausprobiert und es klappt bei mir nicht. Hat sich inzwischen etwas, was die Matrixformel betrifft, geändert?
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crystal
crystal     Wolfgang
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Hi Wolfgang,

The formulas provided in this post work well in my case. What result did you get?
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madgrappler
madgrappler
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Thought I would let everyone know that I needed to find the last position of the house numbers in an address field in access. The only way I could do this was to export a short query to excel and run this formula. I know there is a way to get the excel functions in access but this was much easier. I had addresses that had varying house number lengths and then you throw in the 1st, 2nd, 3rd...St., Ave into the mix within the street name and you got a major problem parsing a very bad formatted address string.

address examples 1234 nw (or NW) 4th St.
12 West St North (or N)
123,456, and 789 Heritage Circle (or Crc)
123 & 456 N 1st. St

I figured out a way to parse off the first and second example real quick with some research (I would give credit, but right now I can't remember where I got the answer). It involved creating a VBA function to accomplish it. That worked great but I came to a problem when we come to the first "," or "and" or "&".

Using this formula in excel found the last number I needed without choosing the street number. Since most house numbers ended with a space " " between them and the direction segment or the street name segment, I added --- &" " after the find formula. Like this: in an array formula
=MAX(IFERROR(FIND({1,2,3,4,5,6,7,8,9,0}&" ",E2,ROW(INDIRECT("1:"&LEN(E2)))),0))
A quick export back to an access table and wala! you have the number.
202 & 206 N Blanche Ave = 9

Now I know I could probably parse the rest of the address in excel but it actually worked real well in Access, so I just decided to do the rest there.

If there is a way to do it all in Access, I couldn't find it or figure it out.
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Borja
Borja
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goood, thanks
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Guess
Guess
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That's what I needed =MIN(SEARCH({0,1,2,3,4,5,6,7,8,9},A2&"0123456789"));

thank you very much!
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crystal
crystal     Guess
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You are welcome O(∩_∩)O
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Francis
Francis
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how to get this to work in powerpivot
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crystal
crystal     Francis
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Hi,
Sorry can't help with this.
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LanaMadAboutExcel
LanaMadAboutExcel
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.... and here I thought that I knew Excel well. Bravo!!!!!
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George
George
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And here is a formula for finding the position of the last numeric character in a string, but WITHOUT using an array formula: =MAX(SEARCH(CHAR(9),SUBSTITUTE("0123456789"&A1,{0,1,2,3,4,5,6,7,8,9},CHAR(9),LEN(A1)+10-LEN(SUBSTITUTE("0123456789"&A1,{0,1,2,3,4,5,6,7,8,9},"")))))-10 The number 10 appearing in this formula, are due to the length of the constant string "0123456789", that is concatenated in this formula.
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Mehidy Hassan
Mehidy Hassan     George
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Many Thanks , Great
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Datta
Datta     George
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Hi George, your formula is may meet my requirement. I need similar formula to find out digit position in the string listed in "A" row in B row Required output 8 5 1 4 3 1 3 2 5 5 6 6 1 7 9 9 1 1 6 0 9 3 0 2 7 4 9 3 6 5 5 7 4 9 8 10 2 10 0 8 1 9
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Ashabel
Ashabel
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This was exactly what I wanted. Thank you.
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Jon Adams
Jon Adams
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The function 1). Formula 1: =MIN(SEARCH({0,1,2,3,4,5,6,7,8,9},A2&"0123456789")); It's absolutely what i needed and extremely cool! Thanks so much! Jon
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Wajid
Wajid     Jon Adams
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Hats off mate..
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